Question

14. a train starting from rest moves with a uniform acceleration of 0.2m/s^2 for 5 minutes. Calculate the final velocity acquired and the distance travelled in this time. Ans in more than 30 words

Answer 1

assuming that the train is moving in a straight line
here
acceleration(s)=o.2m/sec^2
time(t)=5min i.e.5*60 sec=300sec
let 'v' be the final velocity and 'u' be the initial velocity
here as the train was initially at rest u=0
by first kinematic equation we get
v=u+at
v=0+0.2*300
v=60 m/sec
therefore final velocity is 60 m/sec int the same direction
distance covered is 
s=ut+1/2at^2
s=1/2*0.2*300*300
s=9000m
therefore the train will cover 9000m or 9km
Hope this helped u
:-)

Answer 2

Answer:

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