Physics, asked by sinharana029, 3 months ago

14. A train starts from a station and moves with a
constant acceleration for 2 minutes. If it covers a
distance of 400 m in this period, find the
acceleration​

Answers

Answered by Anonymous
3

Acceleration of the train = 0.0556 m/s^2

\mathfrak{\underline{\underline{\red{Given: }}}}

 \sf \pink{Distance  \: covered \:  by \:  the  \: train  \: (S)= 400 m.} \\  \sf \pink{Time  \: taken \:  for  \: the  \: travel  \: (t) = 2 m} \\ \sf \pink{  = 2  \times  60  \: seconds = 120 \:  seconds.} \\  \sf \pink{Initial  \: velocity = 0 m/s^2}

 \sf{ :⇒400 = 0 \times 120  +  \frac{1}{2}  \times  a  \times  120^2} \\ \sf{ :⇒400 =  0 + a  \times   \frac{14400}{2}} \\ \sf{ :⇒400 = 7200 \times a} \\ \sf{ :⇒a =  \frac{400}{7200}} \\ \sf{ :⇒a = 0.0556} \\ \sf{Acceleration = 0.0556 m/s^2}

Similar questions