Question

14. A train starts from a station and moves with a
constant acceleration for 2 minutes. If it covers a
distance of 400 m in this period, find the
acceleration.
onotont
accoleration of​

Answer 1

Answer:

hope it help u

mark me as brainly

Answer 2

Explanation:

Given :

• Time (t) = 2 min = 2 × 60 = 120 seconds
• Distance covered (s) = 400 m
• Initial velocity (u) = 0 m/s $\:\:\:\:$ (as train started from rest)

To find :

• Acceleration (a) = ?

Solution :

We know the time taken, distance covered and initial velocity of the train, we have to find acceleration.

We remember, Newton's $\sf{2^{nd}}$ equation of motion i.e, $\green{\sf{s\:=\:ut\:+\:\dfrac{1}{2}at^2}}$

$\longmapsto\:\sf{400\:=\:0\:\times\:120\:+\:\dfrac{1}{2}\:\times\:a\:\times\:(120)^2}$

$\longmapsto\:\sf{400\:=\:\dfrac{1}{2}\:\times\:a\:\times\:14400}$

$\longmapsto\:\sf{400\:=\:a\:\times\:7200}$

$\longmapsto\:\sf{\dfrac{400}{7200}\:=\:a}$

$\small\longmapsto\underline{\boxed{\mathfrak\pink{a\:=\:0.056\:m/s^2}}}$