Question

14. ABCD is a square. P and Q are points on AB and BC such that AQ = DP. Prove that triangle APD is congruent to Triangle BQA.
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Answer 1

it's simple please see the explanation

Step-by-step explanation:

In triangle APD and BQA

AQ = DP Given

AD = AB Side of square

angle PAD = angle QBA each angle of square is 90⁰

hence

triangle APD is congruent to triangle BQA by RHS rule