Question

14. According to Bohr's theory, the energy of radiation in the transition from the third excited state to the first excited state for a hydrogen atom is
(a) 0.85 eV (b) 13.6 eV (c) 2.55 eV (d) 3.4ev
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Answer 1

Explanation:

Answer:

(b) 13.6 eV

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Answer 2

Answer:

The energy of radiation in the transition from the third excited state to the first excited state for a hydrogen atom is 2.55 eV.

Explanation:

Niels Bohr put forth the atomic hydrogen hypothesis in 1913.

He claims that it has a positively charged nucleus composed of protons and neutrons that is encircled by a negatively charged electron cloud.

• The first excited state has an n=2 and the third excited state has an n=4 value.
  ∴$E_{4}$ −$E_{2}$ =−13.6[$\frac{1}{4^{2} } -\frac{1}{2^{2} }$]
                 =−13.6 [$\frac{1}{16} -\frac{1}{4}$]

                       = $-13.6 {\frac{3}{20} } = 2.55 eV$ = 2.55 eV

• The energy of radiation in the transition from the third excited state to the first excited state for a hydrogen atom is 2.55 eV.

• Thus, option (c) is the appropriate option.

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