Question

14. Ajay can do a piece of work in 25 days and Sanjay can finish it
in 20 days. They work together for 5 days and then Ajay goes away
In how many days will Sanjay finish the remaining work?
(a) 11 days
(b) 12 days
(c) 14 days
(d) None of these​

Answer 1

Answer:

Step-by-step explanation:

Ajay' s 1 days work = 1/25

Similarly, sanjay's 1 days work = 1/20

Ajays and Sanjay 's together 1 day's work

= (1/25) + (1/20) = (4 + 5)/100 = 9/100

Their 5 day's work together

= 5 x 1 day's work

= 5 x (9/100) = 45/100

Remaining work = 1 - (5/100) = 55/100

Now, this remaining work is done by Sanjay.

Let Sanjay takes N days to complete it.

Then, (1/20) x N = 55/100

⇒ N = (55 x 20)/100

∴ N = 11 days

So, remaining work is done in 11 days by Sanjay.  

thank you

Answer 2

11 days.

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Happy studying!