Question

14 &15 plzz say any1​

Answer 1

14》

$x + \frac{1}{x} = 3$

By squaring on both sides

$(x + \frac{1}{x} ) {}^{2} = {3}^{2}$

${x}^{2} + 2 \times x \times \frac{1}{x} + \frac{1}{x {}^{2} } = 9$

${x}^{2} + 2 + \frac{1}{ {x}^{2} } = 9$

${x}^{2} + \frac{1}{ {x}^{2} } = 9 - 2$

${x}^{2} + \frac{1}{ {x}^{2} } = 7$

15》

$a + b = 9$

On squaring both sides

$(a + b) {}^{2} = {9}^{2}$

$a {}^{2} + {b}^{2} + 2ab = 81$

$45 + 2ab = 81$

$2ab = 81 - 45$

$ab = 36 \div 2$

$ab = 18$

Hope it helps you......