Question

14) An escalator carries 20 passengers of average mass of
60 kg. It travels 4.2 m in height in one minute each floor. What is the minimum power for the escalator
for its operation to lift these passengers from the first floor to the third floor? (Take = 10m/s^2)
A.840 W
B.50400 W
C.5040 W
D.252 W
​

Answer 1

Answer:

ais theanswer

Explanation:

Answer 2

Answer:

P= 840 W

Explanation:

The question is quite confuse

however, the work you done is like the potential energy that the system gains:

W=mgh

i suppose g=10ms2; if different you can do again the calcules

W=(20×60kg)×10ms2×4,2m=50400J

Power is the work divided the time that it takes

P=Wt=50400J60s=840W

if you go from the firt floor to the third foor, it increases the work, but also the time increases and the Power is the same.