Question

14 angle If the angles of AABC are in ratio 1:1:2, respectively (the largest angle being Sec A tan A C), then the value of - is cosec B cot B (a) o (b) 1/2 (c) 1 (d) 3/2​

Answer 1

Answer:

Option a) O is the correct answer.

Answer 2

Given:

The angles are in AABC in ratio 1:1:2.

To find:

The value of $\frac{sec A}{cosec B} -\frac{tanA}{cotB}$.

Step-by-step explanation:

∠$A$+∠$B$+∠$C$=$180^{0}$

$x+x+2x=180^{0}$

$4x=180^{0}$

$x=45^{0}$

Thus,∠$A$$=x=45^{0}$,∠$B$$=x=45^{0}$,∠$C$$=x=90^{0}$.

$\frac{sec A}{cosec B} -\frac{tanA}{cotB}$

$=\frac{\sqrt{2} }{\sqrt{2} } -\frac{1}{1}$

$=1-1$

$=0$

Answer:

Therefore, the value of $\frac{sec A}{cosec B} -\frac{tanA}{cotB}$ $=0$.