Question

14. Ankit tells his daughter, "Ten years ago, I was seven times as old as you were then. Also, five years from now, I shall be four times as old as you will be". Represent this situation algebraically.​

Answer 1

Answer:

Let Ankit age be x and daughter's age be y

Ten years ago:

Ankit's age = x - 10

Daughter's age = y - 10

x - 10 = 7 ( y - 10 )

x - 10 = 7y - 70

x - 7y = -70 + 10

x - 7y = -60

Five years from now:

Ankit's age = x + 5

Daughter's age = y + 5

x + 5 = 4 ( y + 5 )

x + 5 = 4y + 20

x - 4y = 20 - 5

x - 4y = 15

Now you can solve it further by substitution method to find values of x and y