Question

14) Calculate potential at a distance of 40 cm from a charge of 30 µC in a medium of dielectric

constant 2.5

5 4 3 2​

Answer 1

Explanation:

Answer

Given : r=9 cm =0.09 m

Charge Q=3 nC =3×10

−9

C

Potential at a distance 9 cm, V=

r

kQ

where k=9×10

9

∴ V=

0.09

9×10

9

×3×10

−9

=300 V