Question

14 Calculate the arder of the reaction,
whose Rate = k[ NO)² (O₂]​

Answer 1

$hello$

Here rate law is given as:-

rate=k[NO]2[O2]........(1)

[NO](concentration of NO) can be written as Vn 

where n=number of moles and V=volume

From (1)

rate=K[Vn]2[Vn]......(2)

Now,

Volume is related to 1/3rd

From V to 3V

put new volume in (2)

New rate will be

r′=K[V3n]2[V3n]=K(3)2[Vn]2(2)[Vn]=27K[V3n]2[V3n]so,rr′=K[Vn]2[Vn

Therefore, the rate reaction changed by 27times.

I hope my answer helps you .....✌