Question

14. Calculate the force acting on a point charge 4μC placed in an electric field intensity 5N/C.

Answer 1

$\huge \bold {\underline\color{teal} \mathfrak{Answer }}$

Given E = 5N/C, q = 4μC

$E = \frac{F}{q}$

$F = E \times q$

$F= 5 \times 4 = \bold \color{darkgreen}20 \: N$

Hope it helps