Question

14 cm
2. Diameter of cylinder Ais 7 cm, and the height is 14 cm. Diameter of
cylinder Bis 14 cm and height is 7 cm. Without doing any calculations
can you suggest whose volume is greater? Verify it by finding the
volume of both the cylinders. Check whether the cylinder with greater
volume also has greater surface area?​

Answer 1

Step-by-step explanation:

you ask wrong question we don't understand this question

Answer 2

Answer:

I'll give u the correct answer.. Here u are:

Part 1 : The volume of cylinder B is greater than volume of cylinder A.

Reason : Base area of cylinder B is greater than cylinder A.

Part 2 : Volume of cylinder A

$= \pi \: {r}^{2} h$

$= \frac{22}{7} ( \frac{7}{2}) ^{2} \: \times \: 14 \: cm^{3}$

$= 22 \times \frac{7}{2} \times \frac{7}{2} \times 2$

$= 539 \: cm^{3}$

Volume of cylinder B =

$\pi \: {r}^{2} \: h$

$= \frac{22}{7} ( \frac{14}{2} ) {}^{2} \times 7cm^{3}$

$= 22 \times \frac{14}{2} \times \frac{14}{2} \times 2 \: cm^{3}$

$= 1078 \: {cm}^{3}$

∵ 1078 cm³ > 539 cm³

Hence, volume of cylinder B is greater than volume of cylinder A.

Part 3 : SA of cylinder A

$= 2\pi r \: (h + r)$

$= 2 \times \frac{22}{7} \times \frac{7}{2} (14 + \frac{7}{2} ) {cm}^{2}$

$= 22 \times 17.5 \: {cm}^{2}$

$= 385 \: cm^{2}$

SA of cylinder B

$= 2\pi r \: (h + r)$

$= 2 \times \frac{22}{7} \times \frac{14}{2} (7 + \frac{14}{2} ) {cm}^{2}$

$=44 \times 14 {cm}^{2}$

=$616 {cm}^{2}$

Thus, the cylinder with greater volume also has greater surface area.

↑Here is the end of the answer..

Hope it's help u all.