Question

14 cm long wire isbent into a rectangle the length of its diagonal is 15cm what are the length of the rectangle​

Answer 1

Answer:

Unknown

Explanation:

First of all we will calculate the perimeter.

But we know that,

Perimeter of the rectangle = Length of the wire 2(Length + Breadth) = 14

Perimeter of the rectangle = Length + Breadth = 14 / 2 = 7

Now let us assume that,

Length = X

Length + Breadth = 7

X + Breadth = 7

Breadth = 7 - X

Now we will use Pythagoras theorem,

$x^{2}$ + $(7-x )^{2}$$= 15^{2}$

$x^{2}$ + $49 - 14x + x^{2}$ $= 225$

$2x^{2} -14x = 225-49$

$2x^{2} -14x = 176$

$2x^{2} -14x - 176 = 0$

We know that the Discriminant rule,

Discriminant = $b^{2} -4ac$

= $49 - 176 = -174$

After This you can solve after using the formula.