Question

14) DEF is a triangle, right angled at D. If DE = 24 cm, DF = 7 cm. Find EF.
(a) 31 cm
(b) 17 cm
(c) 25 cm
(d) 625 cm​

Answer 1

Step-by-step explanation:

WE KNOW THAT IN A RIGHT ANGLED TRIANGLE - perpendicular² + base² = hypotenuse²

= DF² + DE² = EF²

= 7² + 24² = EF²

= 49 + 576 = EF²

= 625 = EF² = EF = √625 = 25 cm

Answer 2

Given :

• A Right Angled Triangle in which ∠D = 90° , DE = 24 cm and DF = 7 cm .

To Find :

• Measure of EF .

Solution :

$\longmapsto\tt{DE=24\:cm}$

$\longmapsto\tt{DF=7\:cm}$

Using Pythagoras Theroem :

$\longmapsto\tt{{(EF)}^{2}={(DE)}^{2}+{(DF)}^{2}}$

$\longmapsto\tt{{(EF)}^{2}={(24)}^{2}+{(7)}^{2}}$

$\longmapsto\tt{{(EF)}^{2}=576+49}$

$\longmapsto\tt{EF=\sqrt{625}}$

$\longmapsto\tt\bf{EF=25\:cm}$

So , The Measure of EF is 25 cm .

Option c)25 cm is Correct...