14. Draw the graph of x + 3y = 6 and 2x – 3y = 12.
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Answers
Required solution...
We have to draw the graph of equations that are x+3y = 6 and 2x-3y = 12.
~ Firstly let us assume that
- x+3y = 6 is equation 1
- 2x-3y = 12 is equation 2
~ Now let's put x as 0 in equation 1
→ x+3y = 6
→ 0 + 3y = 6
→ 3y = 6
→ y = 6/3
→ y = 2
- We get coordinates as (0,2)
~ Now let's put y as 0 in equation 1
→ x+3y = 6
→ x+3(0) = 6
→ x+0 = 6
→ x = 6
- We get coordinates as (6,0)
~ Now let's put x as 0 in equation 2
→ 2x-3y = 12
→ 2(0)-3y = 12
→ 0-3y = 12
→ -3y = 12
→ y = 12/-3
→ y = -4
- We get coordinates as (0,-4)
~ Now let's put y as 0 in equation 2
→ 2x-3y = 12
→ 2x-3(0) = 12
→ 2x-0 = 12
→ 2x = 12
→ x = 12/2
→ x = 6
- We get coordinates as (6,0)
They intersect at (6,0)
Know more...
The system used for describing the position of a point in the plane is known as cartesian system.
Relation between the signs of the coordinates of a point and the quadrant of a point in which it lie.
1) If the point is in the first quadrant then the point will be in the form of (+,+) since the 1st quadrant is enclosed by the positive x-axis and positive y-axis
2) If the point is in the second quadrant then the point will be in the form of (-,+) since the 2nd quadrant is enclosed by the negative x-axis and positive y-axis
3) If the point is in the third quadrant then the point will be in the form of (-,-) since the 3rd quadrant is enclosed by the negative x-axis and negative y-axis
4) If the point is in the fourth quadrant then the point will be in the form of (+,-) since the 4th quadrant is enclosed by the positive x-axis and negative y-axis
Kindly see this concept from attachment 4th
