Chemistry, asked by adlinlopez22, 4 months ago

14. Equal amount of sodium thiosulphate solution are taken in two test tubes and one of them is

heated. Then equal amounts of dilute HCl are added to both test tubes.

a) In which test tube does the precipitate form faster?

b) which is the substance precipitates here?

c) what is the reason for the increases in the rate of reaction here? Exp​

Answers

Answered by ardrajohnson1
2

Explanation:

I don't know the answer please help me

Answered by HappyJohn
0

The answers are given below:

Explanation:

In the question, it is said that sodium thiosulphate is taken in 2 test tubes in equal quantity. One of the test tube contains sodium thiosulphate is heated. And then dilute HCl is added to both the test tubes.

a) The test tube which is heated containing sodium thiosulphate precipitates faster.

b) The substance which precipitates when dilute HCl is added to sodium thiosulphate when heated is insoluble precipitate of Sulphur.

c) The reason for the increase in rate of reaction is the increase in temperature. It is because when temperature is increased, the frequency of collision increases. This means that the molecules of the solution in the test tube begins to move very fast and collide with one another.

So, due to this increase collision, the reaction rate also increases. Therefore, we can say that when temperature is raised, the reaction rate also increases. And when temperature is lowered, the rate of reaction gets decreased. So they are directly proportional.

Know More:

36 g of HCI dissolves in 100 g of solution. The density of HCI is 1.19 gcm.The molar mass of the HCl solution will be:

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How many moles of HCl are in 75.0 mL of 0.200 M solution?

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