Question

14. Every year a town's population increases by 8%. If the present population is 13905,
what was the population a year ago?​

Answer 1

Step-by-step explanation:

Solution:

Let the last year's population be x.

$\displaystyle{ \sf{Present \: year \: population \: = x + \frac{8}{100} }}$

Present population = 13,905

$\displaystyle{ \sf{So, \: x + \frac{8}{100} = 13905}}$

• Taking LCM

$\displaystyle{ \sf{ \frac{108x }{100} = 13905}}$

• Taking 108/100 to right side

$\displaystyle{ \sf{x = \cancel{13905} \times \frac{100}{ \cancel{108}} }}$

$\displaystyle{ \sf{x = 128.75 \times 100}}$

$\displaystyle{ \sf{x = 12875}}$

Hence, last year's population is 12,875.