14. Find a cubic polynomial with the sum sum of the product of its zeroes taken two at a time and product taken at a time and product of its zeroes are 3,-1/2,5/4 respectively
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Answer:
4x³ - 12x² - 2x - 5
Step-by-step explanation:
Given :
Let a, b, c be the zeroes of the cubic polynomial
Sum of the zeroes = a + b + c = 3
Sum of product of zeroes taken two at a time = ab + bc + ca = - 1/2
Product of zeroes = abc = 5/4
Cubic polynomial = k{ x³ - (a + b + c)x² + (ab + bc + ca)x - abc }
Where k ≠ 0
= k{ x³ - 3x² + (-1/2)x - 5/4 }
= k( x³ - 3x² - x/2 - 5/4 )
When k = 4
= 4( x³ - 3x² - x/2 - 5/4 )
= 4x³ - 12x² - 2x - 5
Therefore the cubic polynomial is 4x³ - 12x² - 2x - 5
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