Question

14)Find quadratic polynomial whose
sum is (-1/5) and product is (1/5)?
*​

Answer 1

Answer:5x^2+x+1=0

Step-by-step explanation:we know the formula,

x^2-Sx+P=0

S=-1/5

P=1/5

x^2-(-1/5x)+1/5=0

x^2+1/5x+1/5=0

5x^2+x+1=0

Answer 2

${\huge{\pink{\underline{\underline{\purple{\mathbb{\bold{\mathcal{AnSwEr..}}}}}}}}}$

${\large{\blue{\bold{\underline{Given:-}}}}}$

• Sum of zeroes = -1/5.

• Product of zeroes = 1/5.

${\large{\blue{\bold{\underline{To\:Find:-}}}}}$

• The quadratic polynomial.

${\large{\blue{\bold{\underline{Concepts\:Used:-}}}}}$

• Sum of zeroes = -b/a.

• Product of zeroes = c/a.

• Form of quadratic polynomial, = k{x²-(sum of zeroes)+(product of zeroes)}, Where k is constant.

☆ Therefore,

▪︎ The required polynomial,

$\sf = {x}^{2} - ( \frac{ - 1}{5})x + ( \frac{1}{5}) \\ \\ = 25 {x}^{2} - ( - 5)x +(5) \\ \\ = 25 {x}^{2} + 5x + 5 \\ \\ = 5 {x}^{2} + x + 1$