14. Find the area of the shaded region in the adjoining figure in which
PQ = 24 cm and QR = 7 cm
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Answer:
161.5cm
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∠QPR=90 (Traingle formed in the semi circle is of 90°
In Traingle QPR
By pythagoras theorem
H2=P2+B2
H2=(7)2+(24)2
H2=49+576
H2=625
H=625
H=25cm
Diameter of circle =25cm
Radius of circle=225
Area of Semi circle=π(r)2
=21×722×225×225
=245.5
Area of traingle=21×b×h
=21×24×7
=12×7
=84
Area of shaded region = Area of semicircle -Area of traingle
=245.5−84
=161.5cm
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