14. Find the area of the trapezium ABCD in which
AB//DC, AB = 18 cm, B = ZC = 90° ,
CD = 12 cm and AD = 10 cm.
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Answer:
In trapezium ABCD,
AB ∥ DC, AB = 18 cm
∠B = ∠C = 90° , CD = 12 cm and AD = 10cm
Area of trapezium ABCD
Draw DL ⊥ AB
∴ AL = 18 – 12 = 6 cm
AL = BC
Now, area of trapezium = 1/2 (AB + CD) × AL
= 1/2 (18 + 12) × 8 cm2
= 1/2 × 30 × 8 = 120 cm2
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