Question

14. Find the cost of painting of the outer surface of a closed box which is 13 m long, 10 m broad and

12 cm high at the rate of E15 per 1m
^2

​

Answer 1

Answer:

Step-by-step explanation:

Length of the box (l)= 13 m

Breadth of the box (b)= 10 m

Height of the box (h)= 12 m

Total surface area of the box =2(lb×bh×hl)

=2(13×10+10×12+12×13) m^2  

 

=2(130+120+156) m^2  

 

=2×406 m^2  

 

=812 m^2

Cost of painting 1 m^2 = Rs.15

Cost Of Painting 812 m^2 = Rs.12,180

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Answer 2

LENGTH OF THE BOX=13m

BREADTH OF THE BOX=10m

HEIGHT OF THE BOX=12Cm = 0.12m

Total surface area of the box = 2(lb × hb ×hl)

2(13×10 × 0.12×10 × 0.12×13)

2(130 × 1.2 × 1.56)

2(243.36)

486.72 sqm

NOW. COST= RATE×AREA

= 15×486.72

=7300.8 answer

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