Math, asked by priyanka011, 1 year ago

14. Find the difference between the simple interest
and compound interest on ₹12500 for 3 years at
12% p.a. compounded annually.

Answers

Answered by shashikant40
1

Step-by-step explanation:

p=22500

time=3

rate=12%

si=P R T/100

22500×3×12/100

=8100

CI= p(1+R/100)^T - 1

22500(1+12/100)^3 -1

22500×(28×28×28-25×25×25)/25×25×25

=9110.88

CI-Si =9110.88 - 8100

=1010.88

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