Question

14. Find the geometric mean of first five terms of the geometric progression for which a =
$\frac{2.3^{n} }{5}$

.



(Where, nE N
(1) 81/5
(2) 54
(3)54/5
(4) 27 ​

Answer 1

Answer:

256

Step-by-step explanation:

Let a and d be the first term and common ratio of the GP respectively.

Given a=1 and d=4.

Now, a

n

=ar

n−1

∴a

1

=a=1

a

2

=ar=1×4=4

a

3

=ar

2

=1×(4)

2

=16

a

4

=ar

3

=1×(4)

3

=64

a

5

=ar

4

=1×(4)

4

=256