14. Find the number of metallic circular disc with 1.5 cm base diameter and of height 0.2 cm to be melted to form a right circular cylinder of height 10 cm and diameter 4.5 cm.
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let n is the number of metallic disc
now,
volume of all metallic disc=volume of circular cylinder
n. pi.r^2.h=pi.R^2.H
n=R^2.H/r^2.h
given R= 4.5/2cm
H=10cm
r=1.5/2cm
h=0.2cm
hence=(4.5/2)^2.10/(1.5/2)^2. (0.2)
=(4.5 x 4.5 x 10)/(1.5 x 1.5 x 0.2)
=9 x 50=450
hence 450 metallic disc
now,
volume of all metallic disc=volume of circular cylinder
n. pi.r^2.h=pi.R^2.H
n=R^2.H/r^2.h
given R= 4.5/2cm
H=10cm
r=1.5/2cm
h=0.2cm
hence=(4.5/2)^2.10/(1.5/2)^2. (0.2)
=(4.5 x 4.5 x 10)/(1.5 x 1.5 x 0.2)
=9 x 50=450
hence 450 metallic disc
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