Question

14. Find the perimeter of the figure in which a semicircle is drawn on BC as

diameter. BAC = 90°.

B C

A

5 cm 12 cm​

Answer 1

Answer:

bjjjuuejjejhessshhhddhddd

Answer 2

262/7

Step-by-step explanation:

In the figure it is given that the AB = 5 cm and AC =12 cm and angle BAC = 90°

we have to find the perimeter of the figure

In rt ∆BAC

By Pythagoras theoram

(BC)^2 = (AB) ^2 + (AC) ^2

(BC)^2= (5) ^2 + (12) ^2

(BC) ^2 = 25 + 144

(BC) ^2 = 169

(BC) = √169

BC=13 cm

perimeter of figure = perimeter of semicircle + length of AB +AC

perimeter of figure = πd/ 2 + 5 + 12

perimeter of figure = 22/7 × 13 × 1/2 + 5 + 12

I have not added the third side of triangle because it is already added in the perimeter of senicircle as diameter

perimeter of figure = 143/7 + 17

perimeter of figure = 119 + 143 / 7

perimeter of figure = 262/7

Hope it will help you

Thanks.....