Question

14. Find the quadratic polynomial whose zeroes are 1/4 and 1/2​

Answer 1

Please refer the attachment

Answer 2

Answer:

8$x^{2}$+6x-1=0

Step-by-step explanation:

Here given the two zeroes 1/4 and 1/2 and we have to find out the quadratic polynomial

• As we know that to form a polynomial Equation we use the following general form
• $x^{2}$ + (sum of the roots/zeroes)x-(product of the roots)=0

So now put the root values in the above general form

$x^{2}$+ ( 1/4 +1/2)x - (1/4 * 1/2)=0 on solving this we get

$x^{2}$+3/4 x- 1/8=0 or we can write in other form by multiplying whole equation by 8 we get -- 8$x^{2}$+6x-1=0