Question

14) Find the quadratic polynomial whose zeros are 2 and -6 . * (a) x²+ 4x + 12 (b) x²– 4x – 12 (c) x² + 4x – 12 (d) x²– 4x + 12​

Answer 1

Answer:

To Find

• Quadratic polynomial.

$\sf \: \pink{Solution:-}$

$\sf \: ⇒ Given \: zeros \: are \: α=2 \: and \: β=−6.$

$\sf \: ⇒ Sum \: of \: zeros \: =α+β=2+(−6)=−4$

$\sf⇒ Product \: of \: zeros \: =α×β=2×(−6)=−12$

$\sf⇒  Quadratic \: polynomial = \: x {}^{2} −(α+β)x+(α×β)$

$\sf \: ⇒  Quadratic \: polynomial =x {}^{2} −(−4)x+(−12)$

$\sf \: ∴  \:  Quadratic \: polynomial =x {}^{2} +4x−12$

x² + 4x – 12

Hence, This is Answer.