14. For a certain metal v = 2v, and the electrons come out
with a maximum velocity of 4 x 10 m/s. If the value of
v = 5v, then maximum velocity of photoelectrons will
be:
(a) 2 x 107 m/s
(b) 8 x 106 m/s
(c) 2 x 106 m/s
(d) 8 x 105 m/s
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Answer:Given the frequency of excitation is given as : ν
0
Given initial frequency =ν=5ν
0
5hν
0
−hν
0
=
2
1
mv
1
2
=4hν
0
Given that final frequency =ν=2ν
0
2hν
0
−hν
0
=
2
1
mv
2
2
=hν
0
Dividing the two:
v
1
2
v
2
2
=
4
1
v
2
=
2
1
v
1
=
2
1
8×10
6
=4×10
6
m/s
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