Question

14. For a certain metal v = 2v, and the electrons come out
with a maximum velocity of 4 x 10 m/s. If the value of
v = 5v, then maximum velocity of photoelectrons will
be:
(a) 2 x 107 m/s
(b) 8 x 106 m/s
(c) 2 x 106 m/s
(d) 8 x 105 m/s​

Answer 1

Answer:

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Answer 2

Answer:Given the frequency of excitation is given as : ν  

0

​  

 

Given initial frequency =ν=5ν  

0

​  

 

5hν  

0

​  

−hν  

0

​  

=  

2

1

​  

mv  

1

2

​  

=4hν  

0

​  

 

Given that final frequency =ν=2ν  

0

​  

 

2hν  

0

​  

−hν  

0

​  

=  

2

1

​  

mv  

2

2

​  

=hν  

0

​  

 

Dividing the two:

v  

1

2

​  

 

v  

2

2

​  

 

​  

=  

4

1

​  

 

v  

2

​  

=  

2

1

​  

v  

1

​  

=  

2

1

​  

8×10  

6

=4×10  

6

m/s

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