Math, asked by sandeepasoni7, 1 month ago

14. Given: 5 cos A - 12 sin A = 0; evaluate :
sin A +cos A
2 cos A-sin A​

Answers

Answered by harshverma21
0

Answer:

Correct option is

A

19

5cosA−12sinA=0

tanA=

12

5

Now,

2cosA−sinA

sinA+cosA

Multiply and divide by cosA

=

2−tanA

tanA+1

=

2−

12

5

12

5

+1

=

12

24−5

12

5+12

=

19

17

Answered by anshm9970
0

Answer:

5cosA−12sinA=0

tanA=

12

5

Now,

2cosA−sinA

sinA+cosA

Multiply and divide by cosA

=

2−tanA

tanA+1

=

2−

12

5

12

5

+1

=

12

24−5

12

5+12

=

19

17

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