14 -i
14 -ii
please sovethis . is urgent .
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this is the answer i thought
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(i)
![\sqrt[5]{5x + 2 } = 2 \\ { \sqrt[5]{5x + 2} }^{5} = {2}^{5 } \\ 5x + 2 = 32 \\ 5x = 30 \\ x = 6](https://tex.z-dn.net/?f=+%5Csqrt%5B5%5D%7B5x+%2B+2+%7D++%3D+2+%5C%5C++%7B+%5Csqrt%5B5%5D%7B5x+%2B+2%7D+%7D%5E%7B5%7D++%3D++%7B2%7D%5E%7B5+%7D++%5C%5C+5x+%2B+2+%3D+32+%5C%5C+5x+%3D+30+%5C%5C+x+%3D+6 "\sqrt[5]{5x + 2 } = 2 \\ { \sqrt[5]{5x + 2} }^{5} = {2}^{5 } \\ 5x + 2 = 32 \\ 5x = 30 \\ x = 6")
(ii)
![\sqrt[3]{3x - 2} = 4 \\ { \sqrt[3]{3x - 2} }^{3} = {4}^{3} \\ 3x - 2 = 64 \\ 3x = 66 \\ x = 22](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B3x+-+2%7D++%3D+4+%5C%5C+++++%7B+%5Csqrt%5B3%5D%7B3x+-+2%7D+%7D%5E%7B3%7D++%3D++%7B4%7D%5E%7B3%7D++%5C%5C+3x+-+2+%3D+64+%5C%5C+3x+%3D+66+%5C%5C+x+%3D+22 "\sqrt[3]{3x - 2} = 4 \\ { \sqrt[3]{3x - 2} }^{3} = {4}^{3} \\ 3x - 2 = 64 \\ 3x = 66 \\ x = 22")
so these are the answers
(ii)
so these are the answers
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