Question

14. If 3 tan 0 = 4, show that
(3 sin 0 + 2 cos 0)
(3 sin 0 - 2 cos 0)
=3.
​

Answer 1

Answer:

given that

3 tan 0= 4

= sin0=4 , cos0= 3

= sin0/cos0= tan0

3sin 0 + 2cos0= 3*4+2*3= 12+6 = 18

3sin 0 - 2cos0= 3*4-2*3= 12-6 = 6

therefore 18/6 =. 3

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