14. If 3x + 4y = 16 and xy = 4; find the value of
9xsq + 16y sq
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3x + 4 y= 16
squaring
9x^2 + 16 y^2 + 2(3x)(4y)= 256
9 x^2 + 16 y^2 + 24 xy = 256
As xy= 4
9 x^2 + 16 y^2 +24(4)= 256
9 x^2 + 16 y^2 + 96 = 256
9 x^2 + 16 x^2= 256 -96 = 160
tanisha8994:
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