Question

(14) If 5 years ago, the age of a
father was 7 times his sons age
at that time and 5 years from
now, fathers age is 3 times the
age of his son, then the present
age of the father is :​

Answer 1

Answer:

His father is 50 years old

Step-by-step explanation:

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Answer 2

Answer:

40 years.

Step-by-step explanation:

Let the five years ago the age of his son be x years and age of father be 7x years.

present age of son = x+5

present age of father = 7x+5

Five years later their age will (x+10) and (7x+10)

7x+10 = 3×(x+10)

7x-3x = 20

4x = 20

x = 5

so, the present age of son = (x+5) = (5+5) = 10 years

and the present age of father = (7x+5) = (35+5) = 40 years.

Ans: 40 years.