Question

14. If A(5,2), B(2,-2) and C(-2, t) are the vertices of a right angled triangle with
ZB = 90°, then find the value of t.
[3]​

Answer 1

Answer:

Using Pythagoras theorem in right triangle ABC, we obtain

AC2=AB2+BC2

⇒(5+2)2+(2−t)2={(5−2)2+(2+2)2}+{(2+2)2+(−2−t)2}

⇒49+(4−4t+t2)=(9+16)+(16+4+4t+t2)

⇒t2−4t+53=t2+4t×45

⇒−8t=−8

⇒t=1

Answer 2

Step-by-step explanation:

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