Math, asked by suhanikumari49260, 7 months ago

14. If a man travels at a speed of 30 km/h, he
reaches his destination 10 min late and if he
travels at a speed of 42 km/h, he reaches his
destination 10min early. The distance
travelled is
(a) 36 km (b) 35 km (c) 40 km (d) 42 km



please answer me friends ​

Answers

Answered by Rohit57RA
4

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Answered by sonaliravi1987
3

Answer:

Let the distance be x km.

Then, correct time at a speed of

30 km / h = \( \Large \frac{x}{30} \) - \( \Large \frac{10}{60} \)

Correct time at a speed of 42 km /h

= \( \Large \frac{x}{42} \) + \( \Large \frac{10}{60} \)

=> \( \Large \frac{x}{30} \) - \( \Large \frac{10}{60} \) = \( \Large \frac{x}{42} \) + \( \Large \frac{10}{60} \)

=> \( \Large \frac{x}{30} \) - \( \Large \frac{x}{42} \) = \( \Large \frac{2}{6} \)

=> \( \Large \frac{x (12) }{1260} \) = \( \Large \frac{2}{6} \)

=> 72 x = 1260 \( \Large \times \) 2

=> x = \( \Large \frac{1260 \times 2}{72} \) => x = 35 km

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