Math, asked by golisomasekhar144, 10 months ago

14. If a person walks from his house to office at 4/5 of his usual speed, he is late by
15min. Then find the difference in time taken when he walks at 5/4 of his usual
speed?​

Answers

Answered by vansh1385
0

Step-by-step explanation:

i thing this will help you

Attachments:
Answered by saibalaji29varada
0

Answer:

Step-by-step explanation:

4/5 of his usual speed=4*15=60

actual euate it

5parts=60

1part=12

5/4 of his usual speed=5*12/4*12=60/48

usual time -5/4of speed=60-48=12

late by 15mins =12+15=27

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