Math, asked by aruchithagurrala, 7 months ago

14) If A = (x:x²-16=0,2 ER} and B-{x:x² bx
+6 = 0,X ER} then find AUB,ANB,A-B, B-A.

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Answered by sankalpkumar2008

Answer:

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14) If A = (x:x²-16=0,2 ER} and B-{x:x² bx+6 = 0,X ER} then find AUB,ANB,A-B, B-A.​

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14) If A = (x:x²-16=0,2 ER} and B-{x:x² bx
+6 = 0,X ER} then find AUB,ANB,A-B, B-A.