Question

14. If cos A =1/2 and sinB =1/√2, find the value of
TanA-TanB/
1+tanA tanB
​

Answer 1

Step-by-step explanation:

by inverse formula we get the value of A,B

then we put value of A and B in the respective term and and put the value of tan60,tan45(by memory) and in the last simple calculation by rationalisation we get finally value.

Answer 2

Answer:

0

Step-by-step explanation:

cosA=1/2 so angle A= 60

sinB=1/2^½ so angle B=60

now,

tanA=3^½ and tanB=3^½

therefore, tanA-TanB =0

so ans is 0...