Question

14) If KE of a body increases by 300%, by what % will the linear momentum of the body increase?
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Answer 1

Explanation:

follow the steps for answer.

KE=P^2/2m

so , P=√2KE.m

300% of KE = 3KE

so, increase in KE = 3KE

final KE = 4KE

final P=√2×4KE×m=√8KE.m

% increase in P =

[(√8KE.m -√2KE.m) /√2KE.m]×100

=100% increase