14 If r = (1-cos t) i+(t-sin t)j then find dr/dt.
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Concept:
d ( sin x) / dx = cos x
d ( cos x ) / dx = - sin x
Given:
We are given that:
r = ( 1 - cos t ) i + ( t - sin t ) j
Find:
We need to find dr / dt.
Step-by-step explanation:
r = ( 1 - cos t ) i + ( t - sin t ) j
Differentiating both sides with respect to t:
dr / dt = d [ ( 1 - cos t ) i + ( t - sin t ) j ] / dt
The differentiation of sin x is cos x and cos x is - sin x
Using it, we get that:
dr / dt = (0 - ( - sin t) ) i + ( 1 - cos t ) j
dr / dt = ( sin t ) i + ( 1 - cost t ) j.
Therefore, after differentiating r with respect to t, we get the answer as ( sin t ) i + ( 1 - cost t ) j.
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