Question

14. If sec A+ tan A=x, then tan A​

Answer 1

Answer:tanA = (x^2 - 1)/x

Step-by-step explanation:

secA + tanA = X........(1)

We know that :

1 + tanA^2 = secA^2

1 = sec^2A - tan^2A

1 = (secA + tanA) (secA - tanA)

secA + tanA = 1/secA - tanA

So,

X = 1/secA - tanA

SecA - tanA = 1/X..........(2)

Subtract eq^n2 from eq^n1

secA + tanA = X

secA - tanA = 1/X

- + -

tanA = x - 1/x

tanA = (x^2 - 1)/x

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