Question

14. If the distance between the points (4, P) and (1, 0) is 5, then the
value of P is​

Answer 1

Answer:

x (4,p) y (1,0)

distance is 5

root of (X2-x1)^2+(y2-y1)^2 = 5

(1-4)^2 +(0-p)^2 = 5^2

9 + p^2 = 25

p^2 16

p= 4