Question

14. If the point (2K-3, K+2) lies on the graph
of the linear equation 2x +3y +15=0
find the value of k.​

Answer 1

Answer:

K=-15/7

Step-by-step explanation:

if point (2K-3,K+2) lies on the graph of linear equation 2x + 3y + 15 = 0

then points will satisfy the eq. of graph

2(2K-3) + 3(K+2) + 15= 0

4K -6 + 3K +6 +15=0

7K + 15 =0

7K=-15

K= -15/7

Hope it helps you