Question

14) If the value of n +l) is more than 3 and less than 6, what will be the possible number of orbitals ? 2 A) 10 B) 11 C) 13 D) 6​

Answer 1

Answer:

The rules for determining the values of n and l are:

l = 0,1,2…n-1.

n = 0,1,2…

Here we have 3<n+l <6.

so the possible values for n+l are 4 and 5, which narrows down the possible values of n to 3,4 and 5.

based on this the l values for each on the n values respectively are

1,2(3p,3d)

0,1(4s,4p)

0(5s)

there you have it.

5 orbitals are possible for 3<n+l <6.

Explanation:

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