Question

14. If three numbers 12,k,20 are in AP then the value of k is​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

If a number sequence in an Arithmetic Progression.

⇒ there is a constant difference between consecrative terms

⇒ Term 2 - Term 1 = Term 3 - Term 2

Find the difference between term 2 and term 1:

Term 2 = k

Term 1 = 12

Difference = k - 12

Find the difference between term 3 and term 2:

Term 3 = 20

Term 2 = k

Difference = 20 - k

Solve k:

k - 12 = 20 - k

k + k = 20 + 12

2k = 32

k = 16

Answer: The value of k is 16.