Question

14. If three numbers 12, k², 20 are in AP then the value of k is​

Answer 1

$\textbf{Concept used:}$

$\text{If the numbers a,b and c are in A.P, then}$

$\displaystyle\bf\;b=\frac{a+c}{2}$

$\textbf{Given: 12, k^2 , 20 are in A.P}$

$\text{Then,}\;\displaystyle\;k^2=\frac{12+20}{2}$

$\imples\;\displaystyle\;k^2=\frac{32}{2}$

$\imples\;\displaystyle\;k^2=16$

$\imples\;\displaystyle\;k=\pm\,4$

$\therefore\textbf{The value of k are 4, -4}$

Find more:

Find the four numbers in A.P. whose sum is 50 and in which the greatest number is 4 times the least.

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