Question

14. If two angles of a
quadrilateral are 77º and
57° and out of the
remaining two angles, one
angle is 10° smaller than
the other, find these
angles.​

Answer 1

Answer:

57 + 77 + x + (x-10) =360.

134 + 2x-10 = 360.

2x-10 = 360 - 134.

2x-10 = 226

2x = 226+10

2x = 236

x = 236/2

x = 118 degrees

Answer 2

Answer:

let the 1st angle be x+10 and 2nd be x

A.T.Q.

77+57+x+x+10=360

144+2x=360

2x=360-144

2x=216

x=108

1st angle is 118°

2nd angle is 108°

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